Geometry

Trigonometry

Medium

If $\sin A = \frac45$ , then $(3 - \tan A) (2 + \cos A) =$

$\frac{12}{5}$

$\frac{13}{5}$

$\frac{11}{5}$

$3$

✅ Correct Option: Drop

$\sin A = \frac{4}{5}$

$\tan A = \frac{4}{3}$

$(3 - \tan A)(2 + \cos A) = \left(3 - \frac{4}{3}\right)\left(2 + \frac{3}{5}\right) = \frac{13}{3}$

However, NTA didn't provide the correct answer in the option... and the question was dropped!

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Solution

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CUET General Test Past Year Questions (Topic-Wise)

If $\sin A = \frac45$ , then $(3 - \tan A) (2 + \cos A) =$