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A train running at the speed of 80 km/h crosses a 350 m long tunnel in 36 seconds. The length of the train (in m) is:

Solution

Correct Option: 4

Let the length of the train be LL meters. The total distance covered by the train while crossing the tunnel is the length of the train plus the length of the tunnel, which is L+350L + 350 meters.

The speed of the train is 80 km/h, which can be converted to meters per second:

80 km/h=80×10003600=80000360022.22 m/s80 \text{ km/h} = \frac{80 \times 1000}{3600} = \frac{80000}{3600} \approx 22.22 \text{ m/s}.

The time taken to cross the tunnel is 36 seconds. Therefore, the distance covered in that time is:

Distance=Speed×Time=22.22×36800 m\text{Distance} = \text{Speed} \times \text{Time} = 22.22 \times 36 \approx 800 \text{ m}.

Setting up the equation:

L+350=800L + 350 = 800.

Solving for LL:

L=800350=450L = 800 - 350 = 450.

Thus, the length of the train is 450450 m.

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