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The present age of Harish is 8 times the sum of the ages of his two sons at present. After 8 years, his age will be 2 times the sum of the ages of his two sons. The present age of Harish (in years) is:

Solution

Correct Option: 2

Let Harish's present age be HH and the sum of the ages of his two sons be SS.

From the first condition, we have:

H=8SH = 8S

After 8 years, Harish's age will be H+8H + 8, and the sum of his sons' ages will be S+16S + 16.

From the second condition, we have:

H+8=2(S+16)H + 8 = 2(S + 16)

Substituting HH from the first equation into the second:

8S+8=2(S+16)8S + 8 = 2(S + 16)

Expanding and simplifying:

8S+8=2S+328S + 8 = 2S + 32

6S=246S = 24

S=4S = 4

Now substituting back to find HH:

H=8S=8×4=32H = 8S = 8 \times 4 = 32

Thus, the present age of Harish is 3232 years.

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