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Find the perimeter of a rhombus whose one diagonal is 16 cm long and area is 240 cm2^2.

Solution

Correct Option: 1

Area of rhombus = 12d1d2\frac{1}{2} d_1 d_2.

240=12×16×d2240 = \frac{1}{2} \times 16 \times d_2, so d2=30d_2 = 30 cm.

Side of rhombus = (d1/2)2+(d2/2)2=82+152=289=17\sqrt{(d_1/2)^2 + (d_2/2)^2} = \sqrt{8^2 + 15^2} = \sqrt{289} = 17 cm.

Perimeter = 4 x 17 = 68 cm.

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