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A man can row a boat at 8 km/h in still water. If the speed of the water current is 2 km/h and it takes him 2 hours to row to a place and come back, then how far (in km) is the place ?

Solution

Correct Option: 1

Let the distance to the place be dd km.

When rowing downstream, the effective speed is 8+2=108 + 2 = 10 km/h.

When rowing upstream, the effective speed is 82=68 - 2 = 6 km/h.

The time taken to row downstream is d10\frac{d}{10} hours, and the time taken to row upstream is d6\frac{d}{6} hours.

The total time for the round trip is given as 2 hours:

d10+d6=2\frac{d}{10} + \frac{d}{6} = 2

To solve for dd, find a common denominator (30):

3d30+5d30=2.\frac{3d}{30} + \frac{5d}{30} = 2.

8d30=2\frac{8d}{30} = 2

8d=608d = 60

d=7.5d = 7.5

Thus, the distance to the place is 7.5 km.

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