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If highest common factor of x2−px−qx^{2}-p x-q and 5x2−3px−15q5 x^{2}-3 p x-15 q is (x−3)(x-3), then value of ( p,q)\left.p, q\right) will be :

Solution

✅ Correct Option: 3

If x−3x-3 is a factor of the expressions, then x−3=0,x-3=0, x=3x=3 should equate both the expressions 0.

Putting x=3x=3 in the first equation:

32−3p−q=03^2-3p-q=0

3p+q=93p+q=9 --> Eq. 1

Putting x=3x=3 in the second equation:

5(3)2−3(3)p−15q=05(3)^2-3(3)p-15q=0

9p+15q=459p+15q=45

=3p+5q=15=3p+5q=15 --> Eq. 2

Subtract Eq. 1 from Eq. 2

4q=64q=6

=q=64=32=q=\frac{6}{4}=\frac{3}{2}

Put this value of q back in Eq. 1, and we'll get p=52p=\frac{5}{2}

Hence, Option 3 is the answer.

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