A cube has each edge 2 cm and cuboid is 1 cm long, 2 cm wide and 3 cm high. The paint in a certain container is sufficient to paint area equal to 54 cm². Which of the following is correct?
Solution
✅ Correct Option: 3
Paint covers surface area, so find the surface area of each solid. | Solid | Surface area formula | Value | |---|---|---| | Cube (edge 2 cm) | $6a^2$ | $6\times2^2=24\text{ cm}^2$ | | Cuboid ($1\times2\times3$) | $2(lb+bh+hl)$ | $2(2+6+3)=22\text{ cm}^2$ | $\text{Paint needed}=24+22=46\text{ cm}^2$ The container covers $54\text{ cm}^2$, and $46<54$. So there is enough paint for both, and both the cube and the cuboid can be painted.