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If pq=37\frac{p}{q}=\frac{3}{7} and rs=59\frac{r}{s}=\frac{5}{9}, the value of 7pr−qs6qs−21pr\frac{7pr-qs}{6qs-21pr} is

Solution

✅ Correct Option: 1

Multiply the two given ratios:

prqs=pq×rs=37×59=521\dfrac{pr}{qs}=\dfrac{p}{q}\times\dfrac{r}{s}=\dfrac{3}{7}\times\dfrac{5}{9}=\dfrac{5}{21}

So take pr=5kpr=5k and qs=21kqs=21k.


Numerator:

7pr−qs=7(5k)−21k7pr-qs=7(5k)-21k

=35k−21k=35k-21k

=14k=14k

Denominator:

6qs−21pr=6(21k)−21(5k)6qs-21pr=6(21k)-21(5k)

=126k−105k=126k-105k

=21k=21k


7pr−qs6qs−21pr=14k21k=23\dfrac{7pr-qs}{6qs-21pr}=\dfrac{14k}{21k}=\dfrac{2}{3}

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