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Seeta got married 6 years ago. Today her age is 1141\frac{1}{4} times her age at the time of her marriage. Her son's age is 110\frac{1}{10} times her present age. What is the present age of her son?

Solution

✅ Correct Option: 3

Let her age at marriage be xx.

The marriage was 6 years ago, so her present age is x+6x+6.

Given,

x+6=114x=54xx+6=1\dfrac{1}{4}x=\dfrac{5}{4}x

⇒4x+24=5x\Rightarrow 4x+24=5x

⇒x=24\Rightarrow x=24

Present age=24+6=30\text{Present age}=24+6=30 years


Son’s age=110×30=3\text{Son's age}=\dfrac{1}{10}\times30=3 years

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