If d/dx[f(x)] = 5x^4 - 2/x^3 such that f(-1/2) = 0, then f(x) is equal to Option 1: x^5 + 1/x^2 - 127/32 Option 2: x^4 - 1/x^3 + 127/32 Option 3: x^5 + 1/x^2 + 127/32 Option 4: x^4 + 1/x^3 - 127/32

The answer is 'x^5 + 1/x^2 - 127/32'. View full solution:

CUET Mathematics - If d/dx[f(x)] = 5x^4 - 2/x^3 such that f(-1/2) = 0, then f(x) is equal to | PYQs + Solutions

CUET Mathematics 2026 25th May Shift 1

Calculus

Easy

common

$x^5 + \dfrac{1}{x^2} - \dfrac{127}{32}$

$x^4 - \dfrac{1}{x^3} + \dfrac{127}{32}$

$x^5 + \dfrac{1}{x^2} + \dfrac{127}{32}$

$x^4 + \dfrac{1}{x^3} - \dfrac{127}{32}$

✅ Correct Option: 1