If = 4, = 3 and +b = 6, then -b = Option 1: sqrt(14) Option 2: 14 Option 3: 42 Option 4: 1

The answer is 'sqrt(14)'. View full solution:

CUET Mathematics - If = 4, = 3 and +b = 6, then -b = | PYQs + Solutions

CUET Mathematics 2026 25th May Shift 1

Algebra

Easy

core

$\sqrt{14}$

$4\sqrt2$

✅ Correct Option: 1

Related questions:

19th May Shift 1

Match List-I with List-II

List-I	List-II
(A) $(\vec{a}-\vec{b}) \times (\vec{a}+\vec{b})$ equals	(I) $\vec{0}$
(B) $\vec{a} = (3\hat{i}+\hat{j}-4\hat{k}), \vec{b} = (6\hat{i}+5\hat{j}-2\hat{k})$ , then $\left\vert \vec{a}\times\vec{b} \right\vert$ equals	(II) $5$
(C) $\vec{a}\times(\vec{b}+\vec{c}) + \vec{b}\times(\vec{c}+\vec{a}) + \vec{c}\times(\vec{a}+\vec{b}) =$	(III) $2(\vec{a}\times\vec{b})$
(D) Projection of vector $(\hat{i}+3\hat{j}+7\hat{k})$ on vector $(2\hat{i}-3\hat{j}+6\hat{k})$ is	(IV) $27$

Choose the correct answer from the options given below:

16 May Shift 1

Which of the following cannot be the direction ratios of the straight line $\frac{x-3}{2}=\frac{2-y}{3}=\frac{z+4}{-1}$ ?

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If $\vec{a} = 2\hat{i} - \hat{j} + 3\hat{k}$ and $\vec{b} = 2\hat{i} + 2\hat{j} + \hat{k}$ , then

Match List-I with List-II

List-I	List-II
(A) Projection of $\vec{a}$ on $\vec{b}$ is	(I) $-7\hat{i} + 4\hat{j} + 6\hat{k}$
(B) $\vec{a} \times \vec{b}$ is	(II) $\frac{1}{\sqrt{101}}(-7\hat{i} + 4\hat{j} + 6\hat{k})$
(C) unit vector along $\vec{a} + \vec{b}$ is	(III) $\frac{5}{3}$
(D) Unit vector perpendicular to both $\vec{a}$ & $\vec{b}$ is	(IV) $\frac{1}{\sqrt{33}}(4\hat{i} + \hat{j} + 4\hat{k})$

Choose the correct answer from the options given below: