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If m and n are the order and the degree of the differential equation :

xd2ydx2=[1+(dydx)2]1/3x\dfrac{d^2y}{dx^2} = \left[1+\left(\dfrac{dy}{dx}\right)^2\right]^{1/3} then which one of the following is TRUE?

Solution

✅ Correct Option: 4

Highest derivative is d2ydx2\dfrac{d^2y}{dx^2}, so m=2m=2.

Cubing both sides removes the fractional power and gives x3(d2ydx2)3x^3\left(\dfrac{d^2y}{dx^2}\right)^3, so n=3n=3.

Then 3m+n=6+3=93m+n=6+3=9.

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