Skip to main contentSkip to solution

In a triangle, △ABC\triangle ABC, the sides AB and AC are represented by vectors i^+j^+k^\hat{i} + \hat{j} + \hat{k} and 2i^−k^2\hat{i} - \hat{k} respectively. The length of median drawn from vertex A to BC is:

Solution

✅ Correct Option: 4

Median from A to midpoint M of BC: AM⃗=AB⃗+AC⃗2=3i^+j^2\vec{AM} = \frac{\vec{AB} + \vec{AC}}{2} = \frac{3\hat{i} + \hat{j}}{2}.

∣AM⃗∣2=9+14=104=52|\vec{AM}|^2 = \frac{9 + 1}{4} = \frac{10}{4} = \frac{5}{2}.

∣AM⃗∣=52|\vec{AM}| = \sqrt{\frac{5}{2}}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question