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The sum of all the values of λ\lambda for which the distance of the point P (2, 3, λ\lambda) from the plane x+2y−2z=9x + 2y - 2z = 9 is 3 units, is

Solution

✅ Correct Option: 2

Distance: ∣2+6−2λ−9∣1+4+4=∣−1−2λ∣3=3\frac{|2 + 6 - 2\lambda - 9|}{\sqrt{1 + 4 + 4}} = \frac{|-1 - 2\lambda|}{3} = 3.

∣2λ+1∣=9|2\lambda + 1| = 9, so 2λ+1=±92\lambda + 1 = \pm 9.

λ=4\lambda = 4 or λ=−5\lambda = -5. Sum =−1= -1.

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