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If f′(x)=4x5−6xf'(x) = 4x^5 - 6x and f(0)=3f(0) = 3, then f(3)f(3) is equal to

Solution

✅ Correct Option: 1

Integrating: f(x)=4x66−3x2+C=2x63−3x2+Cf(x) = \frac{4x^6}{6} - 3x^2 + C = \frac{2x^6}{3} - 3x^2 + C.

f(0)=C=3f(0) = C = 3.

f(3)=2⋅7293−27+3=486−27+3=462f(3) = \frac{2 \cdot 729}{3} - 27 + 3 = 486 - 27 + 3 = 462.

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