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If the order and the degree of the differential equation (dydx)12=(d2ydx2)15\left(\frac{dy}{dx}\right)^{\frac{1}{2}} = \left(\frac{d^2y}{dx^2}\right)^{\frac{1}{5}} are O and S respectively, then S−OS - O is equal to

Solution

✅ Correct Option: 4

Raise both sides to power 10: (dydx)5=(d2ydx2)2(\frac{dy}{dx})^5 = (\frac{d^2y}{dx^2})^2.

Highest derivative is d2ydx2\frac{d^2y}{dx^2}, so order O=2O = 2. Its power is 22, so degree S=2S = 2.

S−O=0S - O = 0.

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