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If ff is a function defined by f(x)={5x2−x+3,x<13x+4,x≥1f(x) = \begin{cases} 5x^2 - x + 3, & x < 1 \\ 3x + 4, & x \geq 1 \end{cases}, then, at x=1x = 1, ff is

Solution

✅ Correct Option: 2

Continuity: lim⁡x→1−f(x)=5−1+3=7=f(1)=3+4=7\lim_{x \to 1^-} f(x) = 5 - 1 + 3 = 7 = f(1) = 3 + 4 = 7. Continuous.

Left derivative: 10x−110x - 1 at x=1x = 1 is 99.

Right derivative: 33 at x=1x = 1.

Left derivative is not equal to right derivative, so not differentiable.

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