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The equation of plane passing through the point of (3, 2, 0) and containing the line x−22=y+34=z−11\frac{x-2}{2} = \frac{y+3}{4} = \frac{z-1}{1} is

Solution

✅ Correct Option: 1

Line passes through (2,−3,1)(2, -3, 1) with direction (2,4,1)(2, 4, 1).

Vector from (3,2,0)(3,2,0) to (2,−3,1)(2,-3,1): (−1,−5,1)(-1,-5,1).

Normal =(−1,−5,1)×(2,4,1)=(−9,3,6)= (-1,-5,1) \times (2,4,1) = (-9, 3, 6), or (3,−1,−2)(3, -1, -2).

Plane: 3(x−3)−(y−2)−2z=03(x-3) - (y-2) - 2z = 0, i.e. 3x−y−2z=73x - y - 2z = 7.

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