The equation of the line passing through (-2, 3, 4) and parallel to the vector 2i - j + k is: Option 1: r = (i + j + k) + (2i - j + k) Option 2: r = (2i - j + k) + (i + j + k) Option 3: r = (-2i + 3j + 4k) + (2i - j + k) Option 4: r = (2i - j + k) + (-2i + 3j + 4k)

The answer is 'r = (-2i + 3j + 4k) + (2i - j + k)'. View full solution:

The equation of the line passing through (-2, 3, 4) and paral<=l to the vector 2i - j + k is:

r = (-2i + 3j + 4k) + (2i - j + k)

r = (2i - j + k) + (-2i + 3j + 4k)

CUET Mathematics 2022 4 Aug Shift 1

Algebra

Easy

$\vec{r} = (\hat{i} + \hat{j} + \hat{k}) + \lambda(2\hat{i} - \hat{j} + \hat{k})$

$\vec{r} = (2\hat{i} - \hat{j} + \hat{k}) + \lambda(\hat{i} + \hat{j} + \hat{k})$

$\vec{r} = (-2\hat{i} + 3\hat{j} + 4\hat{k}) + \lambda(2\hat{i} - \hat{j} + \hat{k})$

$\vec{r} = (2\hat{i} - \hat{j} + \hat{k}) + \lambda(-2\hat{i} + 3\hat{j} + 4\hat{k})$

✅ Correct Option: 3