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The line x+23=y+35=z−64\frac{x+2}{3} = \frac{y+3}{5} = \frac{z-6}{4} passes through (a, 2, c). The value of a and c are:

Solution

✅ Correct Option: 4

Substitute the point (a,2,c)(a, 2, c):

a+23=2+35=c−64\frac{a+2}{3} = \frac{2+3}{5} = \frac{c-6}{4}.

Middle expression =1= 1.

So a+23=1⇒a=1\frac{a+2}{3} = 1 \Rightarrow a = 1.

And c−64=1⇒c=10\frac{c-6}{4} = 1 \Rightarrow c = 10.

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