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If two numbers are selected at random from the first 25 natural numbers, then the probability that their sum will be odd is:

Solution

✅ Correct Option: 4

From 1 to 25: 13 odd numbers, 12 even numbers.

Sum is odd when one number is odd and other is even.

Favorable ways: 13×12=15613 \times 12 = 156.

Total ways to choose 2 from 25: (252)=300\binom{25}{2} = 300.

P=156300=1325P = \frac{156}{300} = \frac{13}{25}.

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