Skip to main contentSkip to solution

If f(x)={tan⁡(π/4−x)cot⁡2x,x≠π/4k,x=π/4f(x) = \begin{cases} \frac{\tan(\pi/4 - x)}{\cot 2x}, & x \neq \pi/4 \\ k, & x = \pi/4 \end{cases} is continuous at x=π/4x = \pi/4, then the value of k is

Solution

✅ Correct Option: 3

Let h=x−π/4h = x - \pi/4, so x→π/4x \to \pi/4 means h→0h \to 0.

Numerator: tan⁡(π/4−x)=tan⁡(−h)=−tan⁡h≈−h\tan(\pi/4 - x) = \tan(-h) = -\tan h \approx -h.

Denominator: cot⁡(2x)=cot⁡(π/2+2h)=−tan⁡(2h)≈−2h\cot(2x) = \cot(\pi/2 + 2h) = -\tan(2h) \approx -2h.

Limit =lim⁡h→0−h−2h=12= \lim_{h \to 0}\frac{-h}{-2h} = \frac{1}{2}.

So k=1/2k = 1/2.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question