Geometry

Solids

Easy

A rectangular block with a volume of 250 cm³ was sliced into two cubes of equal volume. How much greater (in sq.cm) is the combined surface area of the two cubes than the original surface area of the rectangular block?

84.67 cm²

56.25 cm²

50 cm²

48.64 cm²

✅ Correct Option: 3

Each cube has volume $125$ cm³, so its edge is 5 cm and the block measures $5\times5\times10$ .

Block surface area $=2(25+50+50)=250$ cm². Two cubes give $2\times6\times25=300$ cm².

Difference $=300-250=50$ cm², which equals the two new faces exposed by the cut.

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Choose the correct answer from the options given below:

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Match List-I with List-II

List-I	List-II
(Figures, etc.)	(Area/Volume/Diagonal etc.)
(A) Surface area of Cube	(I) $\pi(R^2 - r^2)$
(B) Volume of Right pyramid	(II) $a\sqrt{2}$
(C) Area of Circular Ring	(III) $6a^2$
(D) Diagonal of Square	(IV) $\frac{1}{3}$ (area of base) × height

Choose the correct answer from the options given below:

A rectangular block with a volume of 250 cm³ was sliced into two cubes of equal volume. How much greater (in sq.cm) is the combined surface area of the two cubes than the original surface area of the rectangular block?

Solution

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