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If a metallic rod of 10 cm length and 2 cm radius is stretched into a wire of 40 m length having uniform thickness, then find the radius of the stretched wire.

Solution

✅ Correct Option: 3

When a metal rod is stretched into a wire, the volume remains constant.

Original rod:

Length = 10 cm

Radius = 2 cm

Stretched wire:

Length = 40 m = 4000 cm

Radius = rr (to find)


The rod is a cylinder with volume:

Volume = πr2h\pi r^2 h

Volume = π×(2)2×10\pi \times (2)^2 \times 10

Volume = π×4×10\pi \times 4 \times 10

Volume = 40π40\pi cm³


The stretched wire is also a cylinder with volume:

Volume = π×r2×4000\pi \times r^2 \times 4000


Since the volume remains constant:

40π=π×r2×400040\pi = \pi \times r^2 \times 4000

40=r2×400040 = r^2 \times 4000

r2=404000r^2 = \dfrac{40}{4000}

r2=1100r^2 = \dfrac{1}{100}

r=110r = \dfrac{1}{10}

r=0.1r = 0.1 cm


Therefore, the radius of the stretched wire is 0.10.1 cm.

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