Geometry

Solids

Medium

The base radius and height of a right circular cylinder is in the ratio of 1:7. If the volume is 176 cm $^3$ , the total surface area of the right circular cylinder is:

$\dfrac{1108}{7}$ cm $^2$

$\dfrac{1208}{7}$ cm $^2$

$\dfrac{1308}{7}$ cm $^2$

$\dfrac{1408}{7}$ cm $^2$

✅ Correct Option: 4

Let $r = k$ and $h = 7k$ . Volume $= \pi r^2 h = 7\pi k^3 = 176$ .

With $\pi = 22/7$ : $22k^3 = 176$ , so $k^3 = 8$ and $k = 2$ . Thus $r = 2$ , $h = 14$ .

Total surface area $= 2\pi r(r+h) = 2 \times \frac{22}{7} \times 2 \times 16 = \frac{1408}{7}$ cm $^2$ .

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Solution

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CUET General Test Past Year Questions (Topic-Wise)

The base radius and height of a right circular cylinder is in the ratio of 1:7. If the volume is 176 cm $^3$ , the total surface area of the right circular cylinder is: