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A committee of 5 members is to be formed by selecting out of 6 men and 4 women. In how many different ways the committee can be formed if it should have at least 2 women?

Solution

✅ Correct Option: 3

Count by number of women:

2W, 3M: (42)(63)=6×20=120\binom{4}{2}\binom{6}{3}=6\times20=120.

3W, 2M: (43)(62)=4×15=60\binom{4}{3}\binom{6}{2}=4\times15=60.

4W, 1M: (44)(61)=6\binom{4}{4}\binom{6}{1}=6.

Total =120+60+6=186=120+60+6=186.

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