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40 men can complete a work in 48 days. 56 men started for the same work for x days. After x days, 16 men increased, so, the remaining work is completed in 131313\frac{1}{3} days. Find x?

Solution

✅ Correct Option: 1

Total work =40×48=1920=40\times48=1920 man-days.

After the increase, 72 men work 403\frac{40}{3} days, contributing 72×403=96072\times\frac{40}{3}=960 man-days.

So 56x=1920−960=96056x=1920-960=960, giving x=96056=1207x=\frac{960}{56}=\frac{120}{7} days.

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