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The length of one pair of opposite sides of a square is increased by 4 cm on each side; the ratio of the length and the breadth of the newly formed rectangle becomes 5 : 3. Find the area of the original square?

Solution

✅ Correct Option: 2

Let the square's side be aa. Lengthening one pair of opposite sides by 4 cm gives a rectangle of dimensions (a+4)(a+4) by aa.

Then a+4a=53\frac{a+4}{a}=\frac{5}{3}, so 3a+12=5a3a+12=5a and a=6a=6. Area of the square =62=36=6^2=36 cm².

Note: The phrase 'increased by 4 cm on each side' can also be read as a total gain of 8 cm; we have taken each of the two opposite sides as becoming 4 cm longer.

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