Skip to main contentSkip to solution

The value of (27)3(22)3(27)2+27×22+(22)2\frac{(2 \cdot 7)^3 - (2 \cdot 2)^3}{(2 \cdot 7)^2 + 2 \cdot 7 \times 2 \cdot 2 + (2 \cdot 2)^2} is

Solution

Correct Option: 2

Using the algebraic identity a3b3a2+ab+b2=ab\frac{a^3 - b^3}{a^2 + ab + b^2} = a - b.

Here a=2.7a = 2.7 and b=2.2b = 2.2.

So the expression equals 2.72.2=0.52.7 - 2.2 = 0.5.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question