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Train of 200 meters long takes 18 seconds to cross a man running at 15 kmph in a direction opposite to that of the train. The speed of the train:

Solution

✅ Correct Option: 1

Relative speed =20018= \frac{200}{18} m/s =20018×185=40= \frac{200}{18} \times \frac{18}{5} = 40 kmph.

Since they move in opposite directions, relative speed is the sum of the two speeds.

So train speed =40−15=25= 40 - 15 = 25 kmph.

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