Arithmetic

Time, Speed & Distance

Medium

A girl increase her speed to 11/5 time of his original speed. So, she reaches her school 15 minute before the usual time. What is her usual time?

0.5 Hours

0.45 Hours

0.25 Hours

0.55 Hours

✅ Correct Option: 2

New speed is $\frac{11}{5}$ times original, so new time is $\frac{5}{11}$ of usual time $T$ . Saved time $=T-\frac{5T}{11}=\frac{6T}{11}=\frac{1}{4}$ hr, giving $T=\frac{11}{24}\approx0.458$ hr, closest to 0.45 hours.

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