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If a and b are positive real numbers. Match List-I with List-II

List-IList-II
IdentitiesRelation
(A) (a+b)(a−b)(\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b})(I) =a−b=a-b
(B) (a+b)(a−b)(a+\sqrt{b})(a-\sqrt{b})(II) =a2−b=a^2-b
(C) (a+b)2(\sqrt{a}+\sqrt{b})^2(III) =a−b2=a-b^2
(D) (a)2−(b)4(\sqrt{a})^2-(\sqrt{b})^4(IV) =a+2ab+b=a+2\sqrt{ab}+b

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

Apply (x+y)(x−y)=x2−y2(x+y)(x-y) = x^2 - y^2 and (x+y)2=x2+2xy+y2(x+y)^2 = x^2 + 2xy + y^2.

(A) a−ba - b, so (I).

(B) a2−ba^2 - b, so (II).

(C) a+2ab+ba + 2\sqrt{ab} + b, so (IV).

(D) (a)2=a(\sqrt{a})^2 = a and (b)4=b2(\sqrt{b})^4 = b^2, giving a−b2a - b^2, so (III).

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