In Geometric Progression, if 10th term is 3072 and 6th term is 192. Then 3rd term will be: Option 1: 2 Option 2: 6 Option 3: 12 Option 4: 24

Answer: 24. Solution: Dividing the terms: ar^9/ar^5 = r^4 = 3072/192 = 16, so r = 2. From ar^5 = 192: 32a = 192, giving a = 6. Third term = ar^2 = 6 x 4 = 24.

Quantitative Reasoning

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In Geometric Progression, if 10th term is 3072 and 6th term is 192. Then 3rd term will be:

✅ Correct Option: 4

Dividing the terms: $\frac{ar^9}{ar^5} = r^4 = \frac{3072}{192} = 16$ , so $r = 2$ .

From $ar^5 = 192$ : $32a = 192$ , giving $a = 6$ .

Third term $= ar^2 = 6 \times 4 = 24$ .

2026: 26 May Shift 1

Which of the following list of numbers is/are an Arithmetic Progression?

(A) 6, 12, 18, 24…

(B) 1, 3, 5, 7…

(D) 21, 18, 15…

Choose the correct answer from the options given below:

2022: 26 Aug Shift 1

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2026: 19 May Shift 2

If the 2nd and 10th terms of an Arithmetic Progression (AP) are 6 and -10 respectively, which term of this AP is zero?

2023: 11 June Shift 2

Which should replace the question mark

$(4.25 + 2.75)^2 + ? = 5^3 - (9 \times 8)$

2026: 25 May Shift 1

Determine the Arithmetic Progression whose third term is 5 and the seventh term is 9.

2023: 15 June Shift 2

The sum of an Infinite geometric series is 4 and the sum of the cubes of the terms of the same GP is 192. The common ratio of the original geometric series is:

In Geometric Progression, if 10th term is 3072 and 6th term is 192. Then 3rd term will be:

Solution

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