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The construction work is assign to the Group-I of 7 workers. They complete the task in 12 days. The another Group-II started the same task with same number of workers. They started the work and just after 5th day their 2 workers left the work. Now, in how many days this Group will complete the task ?

Solution

✅ Correct Option: 4

Total work =7×12=84= 7 \times 12 = 84 worker-days.

In the first 5 days, 7 workers do 7×5=357 \times 5 = 35 worker-days, leaving 49.

With 5 workers remaining, time needed =49÷5=9.8= 49 \div 5 = 9.8 days.

Note: The full duration for Group-II is 5+9.8=14.85 + 9.8 = 14.8 days; the options match the days required after the two workers left, so we have read the question that way.

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