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If A and B are mutually exclusive events, then following probability of the events are given below:

(A) P(A) =0.4, P(B) =0.4 and P(AUB)=0.8

(B) P(A) =0.3, P(B) =0.6 and P(AUB)=0.9

(C) P(A) =0.3, P(B) =0.3 and P(AUB)=0.6

(D) P(A) =0.1, P(B) =0.1 and P(AUB)=0.2

which of the following options is correct?

Solution

✅ Correct Option: 3

For mutually exclusive events P(A∩B)=0P(A \cap B) = 0, so P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B).

Check each: 0.4+0.4=0.80.4+0.4=0.8, 0.3+0.6=0.90.3+0.6=0.9, 0.3+0.3=0.60.3+0.3=0.6, 0.1+0.1=0.20.1+0.1=0.2. All four satisfy the addition rule and every probability lies within [0,1][0,1], so all statements are consistent.

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