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X is twice as good a workman as Y and together they finish a piece of work in 18 days. In how many days will X alone finish the work?

Solution

✅ Correct Option: 3

Let Y's one-day work be uu, so X's is 2u2u.

Together 3u=1183u = \frac{1}{18}, giving u=154u = \frac{1}{54}.

X's rate is 254=127\frac{2}{54} = \frac{1}{27}, so X alone needs 27 days.

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