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A and B can do a piece of work in 12 days; B and C together can do it in 15 days. If A is twice as good a workman as C, find the number of days in which B alone can do the work?

Solution

✅ Correct Option: 2

Think of work as a pizza (total = 1 whole pizza). Each person completes a certain portion per day.

Given information:

  • A and B together finish in 12 days
  • B and C together finish in 15 days
  • A is twice as fast as C

Let C's work rate = cc (portion of work/day)

Let A's work rate = 2c2c (since A is twice as good as C)

Let B's work rate = bb (portion of work/day)


From "A and B complete in 12 days":

(2c+b)×12=1(2c + b) \times 12 = 1

2c+b=1122c + b = \dfrac{1}{12} ... Equation (1)


From "B and C complete in 15 days":

(b+c)×15=1(b + c) \times 15 = 1

b+c=115b + c = \dfrac{1}{15} ... Equation (2)


Subtract Equation (2) from Equation (1):

(2c+b)−(c+b)=112−115(2c + b) - (c + b) = \dfrac{1}{12} - \dfrac{1}{15}

c=112−115c = \dfrac{1}{12} - \dfrac{1}{15}

c=560−460c = \dfrac{5}{60} - \dfrac{4}{60}

c=160c = \dfrac{1}{60}


Substitute c=160c = \dfrac{1}{60} into Equation (2):

b+160=115b + \dfrac{1}{60} = \dfrac{1}{15}

b=115−160b = \dfrac{1}{15} - \dfrac{1}{60}

b=460−160b = \dfrac{4}{60} - \dfrac{1}{60}

b=360b = \dfrac{3}{60}

b=120b = \dfrac{1}{20}


If B's rate = 120\dfrac{1}{20} work per day, then B completes 1 full work in 20 days.

Therefore, B alone can do the work in 20 days.

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