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If 6x−10y=106x - 10y = 10 and xx+y=57\frac{x}{x+y} = \frac{5}{7}, then (x-y) is equal to:

Solution

✅ Correct Option: 4

Given 6x−10y=106x - 10y = 10 and xx+y=57\frac{x}{x+y} = \frac{5}{7}, we need to find (x−y)(x-y).


Starting with the second equation:

xx+y=57\frac{x}{x+y} = \frac{5}{7}

7x=5(x+y)7x = 5(x+y)

7x=5x+5y7x = 5x + 5y

2x=5y2x = 5y

x=5y2x = \frac{5y}{2}


Substituting x=5y2x = \frac{5y}{2} into the first equation:

6(5y2)−10y=106\left(\frac{5y}{2}\right) - 10y = 10

30y2−10y=10\frac{30y}{2} - 10y = 10

15y−10y=1015y - 10y = 10

5y=105y = 10

y=2y = 2


Finding the value of xx:

x=5y2x = \frac{5y}{2}

x=5(2)2x = \frac{5(2)}{2}

x=5x = 5


Therefore:

x−y=5−2=3x - y = 5 - 2 = 3

The answer is 33.

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