A sales agent travels a distance of 50 km in 2 hours and 30 minutes. How much faster, in kilometres per hour, on average, must he travel to make such a trip in 5/6 hours less time?
A sales agent travels a distance of 50 km in 2 hours and 30 minutes. How much faster, in kilometres per hour, on average, must he travel to make such a trip in 5/6 hours less time?
Solution
The sales agent needs to cover 50 km in less time. The distance remains the same at 50 km.
Original time = 2 hours 30 minutes = 2.5 hours
Time reduction = 5/6 hours (approximately 0.833 hours)
Original Speed = Distance ÷ Time
Original Speed =
Original Speed = 20 km/h
New Time = Original Time - Time Reduction
New Time =
New Time = hours (or hours)
New Speed = Distance ÷ New Time
New Speed =
New Speed = 30 km/h
Increase in Speed = New Speed - Original Speed
Increase in Speed =
Increase in Speed = km/h
Therefore, the agent must travel 10 km/h faster on average.
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