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Rohit walks 30 m straight from his school towards the North. Then he turns left and walks 20 m. He turns left again and walks 10 m. Finally, he turns left and walks 20 m to reach point A. What is the shortest distance between his school and point A?

Solution

✅ Correct Option: 2

Let the school be at the origin with coordinates (0, 0).

Rohit walks 30 m North from school:

Position = (0, 30)


Rohit turns left (facing West) and walks 20 m:

Position = (-20, 30)


Rohit turns left again (facing South) and walks 10 m:

Position = (-20, 20)


Rohit turns left again (facing East) and walks 20 m to reach point A:

Position A = (0, 20)


The shortest distance between the school at (0, 0) and point A at (0, 20) is:

d=(0−0)2+(20−0)2d = \sqrt{(0-0)^2 + (20-0)^2}

d=0+400d = \sqrt{0 + 400}

d=400d = \sqrt{400}

d=20d = 20 m

Therefore, the shortest distance between the school and point A is 20 m.

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