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Reena is twice as old as Sunita. Three years ago, Reena was three times as old as Sunita. What is present age of Reena?

Solution

✅ Correct Option: 4

Let Sunita's present age =S= S

Let Reena's present age =R= R


Reena is twice as old as Sunita:

R=2SR = 2S


Three years ago, Reena's age was R−3R - 3

Three years ago, Sunita's age was S−3S - 3

At that time, Reena was three times as old as Sunita:

R−3=3(S−3)R - 3 = 3(S - 3)

R−3=3S−9R - 3 = 3S - 9

R=3S−6R = 3S - 6


From the two equations:

R=2SR = 2S

R=3S−6R = 3S - 6

Setting them equal:

2S=3S−62S = 3S - 6

2S−3S=−62S - 3S = -6

−S=−6-S = -6

S=6S = 6


Sunita's present age is 66 years.

Using R=2SR = 2S:

R=2×6R = 2 \times 6

R=12R = 12

Therefore, Reena's present age is 1212 years.

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