Skip to main contentSkip to solution

The equations: x + 4y - 3 = 0 and 2x + 8y - 6 = 0 have

Solution

✅ Correct Option: 4

Equation 1: x+4y−3=0x + 4y - 3 = 0

Equation 2: 2x+8y−6=02x + 8y - 6 = 0


Multiplying Equation 1 by 2:

2×(x+4y−3)=2×02 \times (x + 4y - 3) = 2 \times 0

2x+8y−6=02x + 8y - 6 = 0

This is exactly the same as Equation 2.


Both equations represent the same line, just written in different ways.

When two equations represent the same line, every point on that line satisfies both equations.

Since a line contains infinitely many points, there are infinite solutions.


For equations a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0:

a1a2=b1b2=c1c2\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2} indicates infinite solutions.

For the given equations:

12=48=−3−6=12\dfrac{1}{2} = \dfrac{4}{8} = \dfrac{-3}{-6} = \dfrac{1}{2}

Therefore, the equations have infinite solutions.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question