Skip to main contentSkip to solution

Consider the following statements:

I. If the height of a cylinder is doubled, the area of the curved surface is doubled.

II. If the radius of a hemispherical solid is doubled, its total surface area becomes fourfold.

Which of the above statement(s) is / are true:

Solution

✅ Correct Option: 3

Curved Surface Area of a cylinder =2πrh= 2\pi rh where rr is the radius and hh is the height.

For the original cylinder:

Height =h= h

Curved Surface Area =2πrh= 2\pi rh

When height is doubled:

New height =2h= 2h

New Curved Surface Area =2πr(2h)= 2\pi r(2h)

=4πrh= 4\pi rh

The ratio of new to original curved surface area:

4πrh2πrh=2\dfrac{4\pi rh}{2\pi rh} = 2

The curved surface area is doubled.

Statement I is true.


For a hemispherical solid, the total surface area includes the curved surface and the flat circular base.

Total Surface Area =2πr2+πr2=3πr2= 2\pi r^2 + \pi r^2 = 3\pi r^2

For the original hemisphere:

Radius =r= r

Total Surface Area =3πr2= 3\pi r^2

When radius is doubled:

New radius =2r= 2r

New Total Surface Area =3π(2r)2= 3\pi(2r)^2

=3π(4r2)= 3\pi(4r^2)

=12πr2= 12\pi r^2

The ratio of new to original total surface area:

12πr23πr2=4\dfrac{12\pi r^2}{3\pi r^2} = 4

The total surface area becomes fourfold.

Statement II is true.


Both Statement I and Statement II are true.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question