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A and B together can complete a piece of work in 12 days. A alone can complete the work in 15 days. In how many days can B alone complete the same work?

Solution

✅ Correct Option: 3

One day's work of B =112−115=5−460=160= \dfrac{1}{12} - \dfrac{1}{15} = \dfrac{5 - 4}{60} = \dfrac{1}{60}.

So B alone takes 60 days.

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