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The number of ways a committee consisting of 3 men and 1 women can be formed from 5 men and 3 women, is _________ .

Solution

✅ Correct Option: 2

A committee consisting of 3 men and 1 woman needs to be formed from 5 men and 3 women.


The number of ways to select 3 men from 5 men:

5C3=5!3!×2!^5C_3 = \dfrac{5!}{3! \times 2!}

=5×4×3!3!×2×1= \dfrac{5 \times 4 \times 3!}{3! \times 2 \times 1}

=5×42×1= \dfrac{5 \times 4}{2 \times 1}

=202= \dfrac{20}{2}

=10= 10


The number of ways to select 1 woman from 3 women:

3C1=3!1!×2!^3C_1 = \dfrac{3!}{1! \times 2!}

=3= 3


Since both selections must be made together to form the committee, the results are multiplied:

Total number of ways =10×3= 10 \times 3

=30= 30

Therefore, the number of ways to form the committee is 30.

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