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Solution

✅ Correct Option: 2

The word is DELETE: D-E-L-E-T-E

Total letters = 6 letters


Count each letter:

  • D appears 1 time
  • E appears 3 times
  • L appears 1 time
  • T appears 1 time

The letter E repeats 3 times.


When letters repeat, the formula for arrangements is:

Number of arrangements=n!n1!×n2!×...\text{Number of arrangements} = \frac{n!}{n_1! \times n_2! \times ...}

Where nn is the total number of letters and n1,n2...n_1, n_2... are the number of times each repeating letter appears.


For the word DELETE:

n=6n = 6 (total letters)

E repeats 3 times

Arrangements=6!3!\text{Arrangements} = \frac{6!}{3!}

=6×5×4×3×2×13×2×1= \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1}

=7206= \frac{720}{6}

=120= 120

Therefore, the letters of DELETE can be arranged in 120 different ways.

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