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Mr. X starts walking towards the West. After walking 70 m, then he turns to the left and walks 35 m straight. If he now turns left again and walks 30 m, and then he turns to the left and walks a distance of 35 m. How far will he be from the starting point finally ?

Solution

✅ Correct Option: 4

Let the starting point be the origin with coordinates (0, 0).

Assume West corresponds to the negative x-direction and North corresponds to the positive y-direction.

Mr. X walks 70 m West:

Position: (-70, 0)


Turning left from West means facing South. He walks 35 m South:

Position: (-70, -35)


Turning left from South means facing East. He walks 30 m East:

Position: (-70 + 30, -35) = (-40, -35)


Turning left from East means facing North. He walks 35 m North:

Position: (-40, -35 + 35) = (-40, 0)


The distance from the starting point (0, 0) to the final position (-40, 0) is:

d=(0−(−40))2+(0−0)2d = \sqrt{(0-(-40))^2 + (0-0)^2}

d=402+0d = \sqrt{40^2 + 0}

d=1600d = \sqrt{1600}

d=40d = 40 m

Therefore, Mr. X is 40 m from the starting point.

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