The average of first 99 positive integers is: Option 1: 45 Option 2: 50 Option 3: 55 Option 4: 60

Answer: 50. Solution: Sum of first n integers = (n(n+1))/2. Average = (n+1)/2 = 100/2 = 50.

Arithmetic

Central Tendency

Easy

The average of first 99 positive integers is:

✅ Correct Option: 2

Sum of first $n$ integers $= \frac{n(n+1)}{2}$ . Average $= \frac{n+1}{2} = \frac{100}{2} = 50$ .

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The mode and median of a set of 7 observations are 22.72 and 49.28, respectively. If each of the largest 3 observations of the set is increased by 4, then the median of the new set?

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Find the median of the following data :

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The average of first 99 positive integers is:

Solution

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