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Ankit walks 3 km towards the south, turns left and walks 6 km. Then he turns towards north and walks 5 km. Again he turns towards west, walks 4 km and stops for a while. Then he further walks 2 km. How far is he from his starting position?

Solution

✅ Correct Option: 1

Let the starting position be at origin (0,0)(0, 0) on a coordinate plane.

Ankit walks 3 km towards south:

Position: (0,−3)(0, -3)


He turns left (facing east now) and walks 6 km:

Position: (6,−3)(6, -3)


He turns towards north and walks 5 km:

Position: (6,2)(6, 2)


He turns towards west and walks 4 km:

Position: (2,2)(2, 2)


He further walks 2 km (continuing west):

Final Position: (0,2)(0, 2)


Distance from starting position (0,0)(0, 0) to final position (0,2)(0, 2):

d=(0−0)2+(2−0)2d = \sqrt{(0-0)^2 + (2-0)^2}

d=0+4d = \sqrt{0 + 4}

d=4d = \sqrt{4}

d=2d = 2 km

Therefore, Ankit is 2 km from his starting position.

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