Quantitative Reasoning

Probability

Medium

What is the probability that a leap year selected at random, will have either 53 Sundays or 53 Saturdays ?

$\frac{3}{7}$

$\frac{2}{7}$

$\frac{1}{7}$

$\frac{4}{7}$

✅ Correct Option: 1

A leap year has 366 days = 52 weeks + 2 extra days. The 2 extra days can be: (Sun,Mon), (Mon,Tue), (Tue,Wed), (Wed,Thu), (Thu,Fri), (Fri,Sat), (Sat,Sun) - 7 cases. Favourable for 53 Sundays or 53 Saturdays: (Sun,Mon), (Fri,Sat), (Sat,Sun) = 3 cases. Probability $=\frac{3}{7}$ .

Note: The chosen option 3 (1/7) is incorrect; the correct answer is option 1 (3/7).

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Match the List-I and List-II

List-I	List-II
(A) Probability of getting one head	(I) 3/4
(B) Probability of getting two heads	(II) 1/2
(C) Probability of getting at most one head	(III) 1/4
(D) Probability of getting three heads	(IV) 0

Choose the correct answer from the options given below:

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What is the probability that a leap year selected at random, will have either 53 Sundays or 53 Saturdays ?

Solution

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